0=-0.01x^2+1.22x+3

Solution for 0=-0.01x^2+1.22x+3 equation:

0=-0.01x^2+1.22x+3

We move all terms to the left:

0-(-0.01x^2+1.22x+3)=0

We add all the numbers together, and all the variables

-(-0.01x^2+1.22x+3)=0

We get rid of parentheses

0.01x^2-1.22x-3=0

a = 0.01; b = -1.22; c = -3;
Δ = b2-4ac
Δ = -1.222-4·0.01·(-3)
Δ = 1.6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.22)-\sqrt{1.6084}}{2*0.01}=\frac{1.22-\sqrt{1.6084}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.22)+\sqrt{1.6084}}{2*0.01}=\frac{1.22+\sqrt{1.6084}}{0.02}
$